<?php header("content-type:text/html;charset=utf-8"); include_once("conn.php"); if(!($_POST['bookname']and $_POST['price'] and $_POST['f_time'] and $_POST['type'])){ echo "輸入不允許為空。單擊<a href='javascript:onclick=history.go(-1)'>這里</a> 返回"; }else{ $result = mysqli_query($conn,$sqlstr1); if($result){ $sqlstr1 ="insert into tb_demo02 values(","'.$_POST['bookname'].'","'.$_POST['bookname'].' ","'.$_POST['bookname'].'","'.$_POST['bookname'].'")"; echo "添加成功,點擊<a href='select.php'>這里</a>查看"; }else{ echo "<script>alert('添加失敗');history.go(-1);</script>"; } }?>Parse error: syntax error, unexpected ',' in?C:\xampp\htdocs\11.php?on line?9
PHP管理mysql數據庫中的數據這條語句為什么總出現語法錯誤,我并沒有看到這行出了什么錯誤
慕斯卡5293577
2018-10-13 12:46:01