$(function(){ //1、成功 打印出Peter $.getJSON('data.js', function(json) { console.log(json['programmers'][0]['firstName']) }); //2、出錯 var data = $.getJSON('data.js', function(json) { return json; }); console.log(data['programmers'][0]['firstName']); //3、出錯 var data2; $.getJSON('data.js', function(json) { data2 = json; }); console.log(data2['programmers'][0]['firstName'])})分析一下出錯兩種方式為何不可行,為何無法將獲取的數據存到全局變量?
jquery的$.getJSON方法的疑問
婷婷同學_
2018-08-06 10:05:04
