function aFun(){function _(arg){this.arg = arg;}_.prototype.testFun = function(){console.log('this is prototype testFun')};_.testFun2 = function(){console.log('this is testFunc2');}return _;};var afun = new aFun('123');console.log(object)afun.testFun2(); //可以調用//afun.testFun(); //不是在原型鏈上么？，為啥不可以調用？？？，var aFun2 = (function (){function _(arg){this.arg = arg;}_.prototype.testFun = function(){console.log('this is prototype testFun')};_.testFun2 = function(){console.log('this is testFunc2');}return _;})();var afun2 = new aFun2('ddd');console.log(afun2 instanceof aFun2)//afun2.testFun2(); //不可以調用，為啥？afun2.testFun(); //可以調用，為啥可以？
javascript 函數返回值的問題，請高手解答
開心每一天1111
2018-08-05 05:05:17
