TA貢獻1864條經驗 獲得超6個贊
es6很簡單，如果二維數組是純數字的話這樣
const max = Math.max(...[].concat(...arr)); console.log(max)
不過我看你數組中包含-這樣的字符，就要先過濾一遍
const max = Math.max(...[].concat(...arr.map(_arr => _arr.map(v => isNaN(v) ? 0 : v))));console.log(max)
es5就乖乖循環遍歷吧，怎么寫都是丑的
var max = 0;
arr.forEach(function (_arr) {
_arr.forEach(function (v) {
if (!isNaN(v) && v > max) max = v
})
});
console.log(max)
TA貢獻1828條經驗 獲得超3個贊
var arr = [
['1','15','56'],
['1','15','56'],
['3','-','56'],
['1','78','-'],
['1','-','56'],
];function dparseInt(i){ var j = parseInt(i); if( isNaN(j) ) return 0; return j;var arr = [
['1','15','56'],
['1','15','56'],
['3','-','56'],
['1','78','-'],
['1','-','56'],
];function dparseInt(i){ var j = parseInt(i); if( isNaN(j) ) return 0; return j;
}//數組全是字符先轉為數字var arr1 = arr.map(item=>{ return item.map(i => dparseInt(i));
});console.log(arr1);//兩個Math.max 搞定var result = Math.max(...arr1.map(v=>Math.max(...v)))console.log(result)舉報