首頁猿問注冊和登錄的代碼怎么寫php

注冊和登錄的代碼怎么寫php

Java MySQL JQuery

幸福的小魚兒 2014-09-29 16:03:47

注冊和登錄的代碼怎么寫php

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4 回答

InfiniteLoop

TA貢獻3條經驗獲得超5個贊

注冊頁面

<!doctype?html>
<html>
?<head>
??<meta?charset="UTF-8">
??<meta?name="Generator"?content="EditPlus?">
??<meta?name="Author"?content="">
??<meta?name="Keywords"?content="">
??<meta?name="Description"?content="">
??<title>注冊頁面</title>
?</head>
?<body>
??<form?action="reg.php"?method="post">
????<p>
????????<label>用戶名:</label>
????????<input?type="text"?name="username"?id="txt1"?/>
????</p>
????<p>
????????<label>密碼:</label>
????????<input?type="password"?name="password"?id="pwd1"?/>
????</p>
????<p>
????????<label>確認密碼:</label>
????????<input?type="password"?id="pwd2"?/>
????</p>
????<p>
????????<input?type="submit"?value="注冊"?/>
????</p>
??</form>
?</body>
</html>

php對提交過來的信息的處理

<?php
????//Author:avirtuous
????$con?=?mysql_connect("localhost","root","root")?or?die('Cloud?not?connect:'.mysql_error());
????mysql_select_db("demo",$con);
????$un?=?$_POST['username'];
????$pwd?=?$_POST['password'];
????$result=mysql_query("INSERT?INTO?user?(username,password)?VALUES?($un,$pwd)");
????if($result){
????????echo?"注冊成功";
????}?else?{
????????echo?"注冊失敗";
????}
?>

登陸頁面

<!doctype?html>
<html>
?<head>
??<meta?charset="UTF-8">
??<meta?name="Generator"?content="EditPlus?">
??<meta?name="Author"?content="">
??<meta?name="Keywords"?content="">
??<meta?name="Description"?content="">
??<title>登陸頁面</title>
?</head>
?<body>
??<form?action="login.php"?method="post">
????<p>
????????<label>用戶名:</label>
????????<input?type="text"?name="username"?id="txt1"?/>
????</p>
????<p>
????????<label>密碼:</label>
????????<input?type="password"?name="password"?id="pwd1"?/>
????</p>
????<p>
????????<input?type="submit"?value="登陸"?/>
????</p>
??</form>
?</body>
</html>

登陸頁面的處理

<?php
????//Author:avirtuous
????$con?=?mysql_connect("localhost","root","root")?or?die('Cloud?not?connect:'.mysql_error());
????mysql_select_db("demo",$con);
????$un?=?$_POST['username'];
????$pwd?=?$_POST['password'];
????$result=mysql_query("SELECT?*?from?user?where?username=$un?and?password=$pwd");
????if($result){
????????echo?"登陸成功";
????}?else?{
????????echo?"用戶名或密碼錯誤";
????}
????
?>

這里只做簡單的功能實現，放到實際中還欠缺許多處理

4 反對回復 2014-09-29

InfiniteLoop

TA貢獻3條經驗獲得超5個贊

不好意思之前腦袋短路了 mysql_query()返回的是一個資源標示符，也就是說只要sql語句正確，無論查詢到的結果如何都會返回值，所以對登陸的php頁面做了點修改

<?php
????$con?=?mysql_connect("localhost","root","root")?or?die('Cloud?not?connect:'.mysql_error());
????mysql_select_db("demo",$con);
????$un?=?$_POST['username'];
????$pwd?=?$_POST['password'];
????$result=mysql_query("SELECT?*?from?user?where?username=$un");
????$row?=?mysql_fetch_array($result);
????if($row)?{
????????if($row['password']?==?$pwd)?{
????????????echo?"登陸成功";
????????}?else?{
????????????echo?"密碼錯誤";
????????}
????}?else?{
????????echo?"用戶名不存在";
????}
?>

1 反對回復 2014-10-02