java怎么讀取json格式的數據,再在前端表現出來,做網頁游戲開發的,急用啊,謝謝!
java怎么讀取json格式的數據
冉冉說
2018-07-12 09:09:43
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/** * * @param result JSON字符串 * @param name JSON數組名稱 * @param fields JSON字符串所包含的字段 * @return 返回List<Map<String,Object>>類型的列表,Map<String,Object>對應于 "id":"1"的結構 */ public static List<Map<String, Object>> convertJSON2List(String result, String name, String[] fields) { List<Map<String, Object>> list = new ArrayList<Map<String, Object>>(); try { JSONArray array = new JSONObject(result).getJSONArray(name); for (int i = 0; i < array.length(); i++) { JSONObject object = (JSONObject) array.opt(i); Map<String, Object> map = new HashMap<String, Object>(); for (String str : fields) { map.put(str, object.get(str)); } list.add(map); } } catch (JSONException e) { Log.e("error", e.getMessage()); } return list; }
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做過的一些json數據解析 幾種常用的json數據格式解析
public static Person getPerson(String key,String jsonString){ Person person = new Person(); try { JSONObject jsonObject = new JSONObject(jsonString); JSONObject personObject = jsonObject.getJSONObject("person"); person.setId(personObject.getInt("id")); person.setName(personObject.getString("name")); person.setAddress(personObject.getString("address")); } catch (Exception e) { // TODO: handle exception } return person; } public static List<Person> getPersons(String key,String jsonString){ List<Person> list = new ArrayList<Person>(); try { JSONObject jsonObject = new JSONObject(jsonString); //返回json數組 JSONArray jsonArray = jsonObject.getJSONArray(key); for (int i = 0; i < jsonArray.length(); i++) { JSONObject jsonObject2 = jsonArray.getJSONObject(i); Person person = new Person(); person.setId(jsonObject2.getInt("id")); person.setName(jsonObject2.getString("name")); person.setAddress(jsonObject2.getString("address")); list.add(person); } } catch (Exception e) { // TODO: handle exception } return list; } public static List<String> getList(String key,String jsonString){ List<String> list = new ArrayList<String>(); try { JSONObject jsonObject = new JSONObject(jsonString); JSONArray jsonArray = jsonObject.getJSONArray(key); for (int i = 0; i < jsonArray.length(); i++) { String msg = jsonArray.getString(i); list.add(msg); } } catch (Exception e) { // TODO: handle exception } return list; } public static List<Map<String, Object>> getListMap(String key,String jsonString){ List<Map<String, Object>> list = new ArrayList<Map<String,Object>>(); try { JSONObject jsonObject = new JSONObject(jsonString); JSONArray jsonArray = jsonObject.getJSONArray(key); for (int i = 0; i < jsonArray.length(); i++) { JSONObject jsonObject2 = jsonArray.getJSONObject(i); Map<String, Object> map = new HashMap<String, Object>(); Iterator<String> iterator = jsonObject2.keys(); while (iterator.hasNext()) { String json_key = iterator.next(); Object json_value = jsonObject2.get(json_key); if (json_value == null) { json_value = ""; } map.put(json_key, json_value); } list.add(map); } } catch (Exception e) { // TODO: handle exception } return list; }
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如果有用Struts框架那就好辦了,struts.xml里配置繼承json-defual,一般Struts包都有,在action下個方法,一樣的返回結果 struts.xml中
<result name="返回字符串" type="json"> <param name="includeProperties">傳出去的值,傳出去的值,...</param> </result>
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