laravel我做了前后臺登陸，后臺未登錄跳轉到前臺登陸頁面了。 我想讓后臺未登入跳轉到后臺登陸頁面，前臺未登陸跳轉到前臺登陸頁面。config\auth.php?添加guards中的admin和providers中的admins<?php
'defaults'?=>?[
????'guard'?=>?'web',
????'passwords'?=>?'users',
],
'guards'?=>?[
????'web'?=>?[
????????'driver'?=>?'session',
????????'provider'?=>?'users',
????],
????'api'?=>?[
????????'driver'?=>?'token',
????????'provider'?=>?'users',
????],
????'admin'?=>?[
????????'driver'?=>?'session',
????????'provider'?=>?'admins',
????],
],
'providers'?=>?[
????'users'?=>?[
????????'driver'?=>?'eloquent',
????????'model'?=>?App\User::class,
????],
????'admins'?=>?[
????????'driver'?=>?'eloquent',
????????'model'?=>?App\AdminUser::class,
????],
],
'passwords'?=>?[
????'users'?=>?[
????????'provider'?=>?'users',
????????'table'?=>?'password_resets',
????????'expire'?=>?60,
????],
],路由//登陸頁面
Route::get('/login',?"\App\Http\Controllers\LoginController@index")->name('login');
//登陸行為
Route::post('/login',?"\App\Http\Controllers\LoginController@login");
Route::group(['middleware'?=>?'auth:web'],function?(){
????Route::get('/posts',?'\App\Http\Controllers\PostController@index');
}
//后臺
Route::group(['prefix'?=>?'admin'],?function()?{
????Route::get('/login',?'\App\Admin\Controllers\LoginController@index');
????Route::post('/login',?'\App\Admin\Controllers\LoginController@login');
????Route::get('/logout',?'\App\Admin\Controllers\LoginController@logout');
????Route::group(['middleware'?=>?'auth:admin'],function?(){
????????Route::get('/home',?'\App\Admin\Controllers\HomeController@index');
????});
});遇到的頁面跳轉問題
3 回答
超級無敵大壞蛋
TA貢獻1條經驗 獲得超0個贊
需要在?App\Exceptions\Handler.php 文件修改
<?php
namespace?App\Exceptions;
use?Exception;
use?Illuminate\Auth\AuthenticationException;
use?Illuminate\Foundation\Exceptions\Handler?as?ExceptionHandler;
class?Handler?extends?ExceptionHandler
{
????/**
?????*?A?list?of?the?exception?types?that?should?not?be?reported.
?????*
?????*?@var?array
?????*/
????protected?$dontReport?=?[
????????\Illuminate\Auth\AuthenticationException::class,
????????\Illuminate\Auth\Access\AuthorizationException::class,
????????\Symfony\Component\HttpKernel\Exception\HttpException::class,
????????\Illuminate\Database\Eloquent\ModelNotFoundException::class,
????????\Illuminate\Session\TokenMismatchException::class,
????????\Illuminate\Validation\ValidationException::class,
????];
????/**
?????*?Report?or?log?an?exception.
?????*
?????*?This?is?a?great?spot?to?send?exceptions?to?Sentry,?Bugsnag,?etc.
?????*
?????*?@param??\Exception??$exception
?????*?@return?void
?????*/
????public?function?report(Exception?$exception)
????{
????????parent::report($exception);
????}
????/**
?????*?Render?an?exception?into?an?HTTP?response.
?????*
?????*?@param??\Illuminate\Http\Request??$request
?????*?@param??\Exception??$exception
?????*?@return?\Illuminate\Http\Response
?????*/
????public?function?render($request,?Exception?$exception)
????{
????????return?parent::render($request,?$exception);
????}
????/**
?????*?Convert?an?authentication?exception?into?an?unauthenticated?response.
?????*
?????*?@param??\Illuminate\Http\Request??$request
?????*?@param??\Illuminate\Auth\AuthenticationException??$exception
?????*?@return?\Illuminate\Http\Response
?????*/
????protected?function?unauthenticated($request,?AuthenticationException?$exception)
????{
????????if?($request->expectsJson())?{
????????????return?response()->json(['error'?=>?'Unauthenticated.'],?401);
????????}
????????if?(in_array('admin',?$exception->guards()))?{
????????????return?redirect()->guest('/admin/login');
????????}
????????return?redirect()->guest(route('login'));
????}
}
hallo_monde
TA貢獻3條經驗 獲得超1個贊
后端路由? 加上?
Route::get('/login',?'\App\Admin\Controllers\LoginController@index')->name('login');-
超級無敵大壞蛋我前臺頁面登錄是寫的 Route::get('/login', "\App\Http\Controllers\LoginController@index")->name('login');
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