1.?使用循環輸出23的二進制(知識點:while循環)?
求大神幫忙啊
qq_Sweet小情緒_0
2017-06-07 23:17:39
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public?static?void?main(String[]?args)?{
????int?num?=?23;
????StringBuilder?sb?=?new?StringBuilder();
????int?temp;
????while(num?>?0)?{
????????temp?=?num?%?2;
????????sb.append(temp);
????????num?/=?2;
????}
????System.out.println(sb.reverse().toString());
}TA貢獻1017條經驗 獲得超1032個贊
public?class?Test
{
public?static?void?main(String[]args){
int?a=23;
int?b=a;
String?result="";
while(a!=0){
result=(a%2)+result;
a/=2;
}
System.out.println(b+"的二進制為:"+result);
result=Integer.toBinaryString(b);
System.out.println(b+"的二進制為:"+result);
}
}TA貢獻3593條經驗 獲得超1個贊
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