function?addTogether()?{??//?Function?to?check?if?a?number?is?actually?a?number
??var?checkNum?=?function(num)?{????
??????if?(typeof?num?!==?'number')?{??????
??????????return?undefined;
??????}?else{
??????????return?num;
??????}
??};??
??
??if?(arguments.length?>?1)?{????
??????var?a?=?checkNum(arguments[0]);????
??????var?b?=?checkNum(arguments[1]);????
??????if?(a?===?undefined?||?b?===?undefined)?{??????
??????????return?undefined;
??????}?else?{??????
??????????return?a?+?b;
??????}
??}?else?{??
????????var?c?=?arguments[0];
????????if?(checkNum(c))?{??????
????????????return?function(arg2)?{
????????????????if?(c?===?undefined?||?checkNum(arg2)?===?undefined)?{??????????
????????????????????return?undefined;
????????????????}?else?{????????
????????????????????return?c?+?arg2;
????????????????}
????????????};
????????}
??}
}
addTogether(2)(3);
請問，為什么(3)會是function(arg2)中的參數arg2？
Joy_Strong
2016-09-24 16:58:55
