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j2ee中servlet的一個新手問題,頁面跳轉提示The requested resource is not available.

j2ee中servlet的一個新手問題,頁面跳轉提示The requested resource is not available.

肖小波 2016-08-29 19:53:31
<form action="servlet_in" method="post">?? ??? ?<div class="hom-add-box">?? ??? ??? ?<label>用戶名:</label> <input type="text" id="hom-in-username">?? ??? ?</div>?? ??? ?<div class="hom-add-box">?? ??? ??? ?<label>密碼:</label> <input type="password" id="hom-in-password">?? ??? ?</div>?? ??? ?<div class="hom-add-box">?? ??? ??? ?<label>登陸類型:</label> ?? ??? ??? ?<select>?? ??? ??? ??? ?<option>用戶</option>?? ??? ??? ??? ?<option>管理員</option>?? ??? ??? ?</select>?? ??? ?</div>?? ??? ?<div class="hom-add-box">?? ??? ??? ?<input type="submit" value="登陸" id="submit" />?? ??? ?</div>?? ?</form>servlet_in中dopost是這樣寫的:??? protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {?? ??? ?// TODO Auto-generated method stub?? ??? ?request.setCharacterEncoding("GB18030");?? ??? ?String username=request.getParameter("hom-in-username");?? ??? ?String password=request.getParameter("hom-in-password");?? ??? ?request.setAttribute("name", username);?? ??? ?request.setAttribute("password", password);?? ??? ?request.getRequestDispatcher("hom.jsp").forward(request, response);?? ?}xml配置:<?xml version="1.0" encoding="UTF-8"?><web-app xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns="http://java.sun.com/xml/ns/javaee" xmlns:web="http://java.sun.com/xml/ns/javaee/web-app_2_5.xsd" xsi:schemaLocation="http://java.sun.com/xml/ns/javaee http://java.sun.com/xml/ns/javaee/web-app_3_0.xsd" id="WebApp_ID" version="3.0">? <display-name>j2ee-demo</display-name>? <welcome-file-list>??? <welcome-file>index.html</welcome-file>??? <welcome-file>index.htm</welcome-file>??? <welcome-file>index.jsp</welcome-file>??? <welcome-file>default.html</welcome-file>??? <welcome-file>default.htm</welcome-file>??? <welcome-file>default.jsp</welcome-file>? </welcome-file-list>? <servlet>??? <servlet-name>servlet_in</servlet-name>??? <servlet-class>page.servlet_in</servlet-class>? </servlet>? <servlet-mapping>??? <servlet-name>servlet_in</servlet-name>??? <url-pattern>/servlet_in</url-pattern>? </servlet-mapping></web-app>
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黑女2008

TA貢獻75條經驗 獲得超32個贊

form的action應該是page/servlet_in吧

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1 反對 回復 2016-08-29
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慕粉1555408013

TA貢獻5條經驗 獲得超0個贊

書上說,<url–pattern>的格式如果是“/computerBill”那么action就是"computerBill"
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反對 回復 2017-05-15
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