for (int i = 0; i <5 i++) { Items item = new Items(); System.out.println(Integer.parseInt(s1[i])); stmt.setInt(1, Integer.parseInt(s1[i])); rs = stmt.executeQuery(); while (rs.next()) { item.setId(rs.getInt("id")); item.setName(rs.getString("name")); item.setCity(rs.getString("city")); item.setNumber(rs.getInt("number")); item.setPrice(rs.getInt("price")); item.setPicture(rs.getString("picture")); list.add(item); }當我把Items對象放到for循環上時（如下），獲得的list對象里五個item都是一樣的。為什么會這樣啊。。。????????????????????????????????????????Items item = new Items(); for (int i = 0; i <s1.length-1; i++) { System.out.println(Integer.parseInt(s1[i])); stmt.setInt(1, Integer.parseInt(s1[i])); rs = stmt.executeQuery(); while (rs.next()) { item.setId(rs.getInt("id")); item.setName(rs.getString("name")); item.setCity(rs.getString("city")); item.setNumber(rs.getInt("number")); item.setPrice(rs.getInt("price")); item.setPicture(rs.getString("picture")); list.add(item); }
1 回答
已采納
qq_原來這就是來自北方的漢子_03305421
TA貢獻10條經驗 獲得超1個贊
for(){
while (rs.next()) {
?item = new Items();
//....
list.add(item);
}
}
-
iMcLaren謝謝解答哈。后來回頭又看了一遍java 面向對象的內容。。已經解決了這個疑問。還是要多看書啊~
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