Java中算法
int?m=5; int?n=7; int?x=m*8/(n+2)%m; System.out.println("m:"?+?m); System.out.println("n:"?+?n); System.out.println("x:"?+?x);
為何x輸出為4?
x=5*8/(7+2)%5
? =40/9%5
? =4%5
? =0
不對嗎?望指點迷津...
int?m=5; int?n=7; int?x=m*8/(n+2)%m; System.out.println("m:"?+?m); System.out.println("n:"?+?n); System.out.println("x:"?+?x);
為何x輸出為4?
x=5*8/(7+2)%5
? =40/9%5
? =4%5
? =0
不對嗎?望指點迷津...
2015-08-23
舉報
2015-09-02
樓上是對的
2015-08-23
哈~~懂了!??!4%5=0......4