                        課程
                    
                        /后端開發
                        
                            /Java
                        
                        /JDBC之 “ 對岸的女孩看過來”

求解答java.lang.NumberFormatException: For input string: "姚雪娟"類異常

else if(OPERATION_UPDATE.equals(in.toUpperCase())
?????||OPERATION_UPDATE.substring(0, 1).equals(in.toUpperCase())
?????||OPERATION_UPDATE.equals(pervious)){
????pervious=OPERATION_UPDATE;
????if(1==step){
?????System.out.println("請輸入要修改的員工ID：");
????}else if(2==step){
?????Integer id=null;
?????try {
??????id = Integer.valueOf(in);
??????try {
???????user = action.getById(id);
???????if(user==null){
????????System.out.println("查詢員工信息失敗");
????????step=1;
???????}else{
????????System.out.println("請輸入新的員工信息[姓名]：");
???????}
??????} catch (Exception e) {
???????System.out.println("查詢員工信息失敗");
???????step=1;
??????}
?????} catch (Exception e) {
??????System.out.println("請輸入正確的員工ID：");
??????step=1;
?????}
?????
????}else if(3==step){
?????System.out.println(in);
?????if(-1!=Integer.valueOf(in)){
??????user.setName(in);
?????}???
?????System.out.println("請輸入新的員工信息[性別]：");
????}

這是view層一段代碼，運行update方法時，當輸入姓名為：姚雪娟時，提示

Exception in thread "main" java.lang.NumberFormatException: For input string: "姚雪娟"
?at java.lang.NumberFormatException.forInputString(NumberFormatException.java:48)
?at java.lang.Integer.parseInt(Integer.java:449)
?at java.lang.Integer.valueOf(Integer.java:554)
?at com.view.View.main(View.java:218)

這是怎么回事？