class?Student
{
string?m_strName;
public:
Student();
Student(string?_name);??????????????????//Student(string?_name='Leo')為什么編譯不通過呢？
Student(const?Student?&?stu);
~Student();
void?SetName(string?_name);????????????//void?SetName(string?_name='Leo')同上
string?GetName();
};
Student::Student()
{
????m_strName="";
????cout<<"Student()"<<endl;
}
Student::Student(string?_name)
{
????m_strName=_name;
????cout<<"Student(string?_name)"<<endl;
}
Student::Student(const?Student&?stu)
{
????cout<<"Student(const?Student?&?stu)"<<endl;
}
Student::~Student()
{
????cout<<"~Student"<<endl;
}
void?Student::SetName(string?_name)
{
????m_strName=_name;
????cout<<"SetName(_name)"<<endl;
}
string?Student::GetName()
{
????return?m_strName;
????cout<<"GetName()"<<endl;
}
int?main(void)
{
????//?通過new方式實例化對象*stu
????Student?*stu?=?new?Student();
????//?更改對象的數據成員為“慕課網”
	stu->SetName("慕課網");
????//?打印對象的數據成員
	cout<<stu->GetName()<<endl;
	return?0;
}

如上注釋所示，為什么在申明函數的時候給形參賦值通不過呢？我記得前面的課程里好像有在聲明函數的時候賦值的

希望前輩指點，謝謝