我也是這個問題，跳轉不出來

你還應該在doPost()方法里面添加處理內容

public void doGet(HttpServletRequest request, HttpServletResponse response)

throws ServletException, IOException {

doPost(request, response);

}

項目重新部署一下，重啟Tomcat

表單：

<form action="servlet/LoginServlet" method="post">
??? <label>用戶名：</label><input type="text" name="username" value=""><br>
??? <label>密碼：</label><input type="password" name="password" value=""><br>
??? <input type="submit" value="提交">
??? </form>

LoginServlet:
public void doPost(HttpServletRequest request, HttpServletResponse response)
?? ??? ??? ?throws ServletException, IOException {

?? ??? ?users u = new users();
?? ??? ?String username = request.getParameter("username");
?? ??? ?String password = request.getParameter("password");
?? ??? ?u.setUsername(username);
?? ??? ?u.setPassword(password);
?? ??? ?//判斷用戶名和密碼是否正確
?? ??? ?if(u.getUsername().equals("admin") && u.getPassword().equals("admin")){
?? ??? ??? ?//登錄成功，跳轉到login_success.jsp
?? ??? ??? ?//請求重定向到login_success.jsp
?? ??? ??? ?response.sendRedirect(request.getContextPath()+"/login_success.jsp");
?? ??? ?}else{
?? ??? ??? ?//登錄失敗，跳轉到login_failure.jsp
?? ??? ??? ?response.sendRedirect(request.getContextPath()+"/login_failure.jsp");
?? ??? ?}
?? ??? ?
?? ?}

代碼貼出來啊