select?a.table_schema?as?'數據名',
?	a.table_name?as?'表名',
a.index_name?as??'索引1',
b.index_name?as?'索引2',
a.column_name?as?'重復列名'
from?statistics?a?join?statistics?b?on?
a.table_schema?=?b.table_schema?and?a.table_name?=?b.table_name
and?a.seq_in_index?=?b.seq_in_index?and?a.column_name?=?b.column_name
where?a.seq_in_index?=?1?and?a.index_name?<>?b.index_name