直接使用Python3 字典get方法即可實現
#?Enter?a?code
d?=?{"Alice":?45,?"Bob":?60,?"Candy":?75,?"David":?86,?"Ellena":?49}
print(d.get("Alice",?"None"))?#?dict.get(key,默認返回值)，不指定默認返回值則默認返回None
print(d.get("Bob",?"None"))
print(d.get("Candy",?"None"))
print(d.get("Mimi",?"None"))
print(d.get("David",?"None"))
2023-12-03
d = {
??? 'Alice': 45,
??? 'Bob': 60,
??? 'Candy': 75,
??? 'David': 86,
??? 'Ellena': 49
}
names = ['Alice', 'Bob', 'Candy', 'Mimi', 'David']
for item in names:
??? print('{} score:{}'.format(item,d.get(item)))