請問如何用cout輸出16進制
#include<stdio.h>
#include<iostream>
int?main(int?argc,char?**argv)
{
??????????int?a[5];
??????????std::cout<<"a[1]:"<<a[1]<<"\na[2]:"<<a[2]<<"\na[3]:"<<a[3]<<"\na[4]:"<<a[4]<<std::endl;????
??????????return?0;
}這樣打出來全是0啊，如何16進制輸出呢？
2022-04-15
運用iomanip庫
#include <iostream>
#include <iomanip>
int main()
{
int a[5]={16,17,18,19,20};
std::cout <<std:: hex << "a[1]:" << a[1] << "\na[2]:" << a[2] << "\na[3]:" << a[3] << "\na[4]:" << a[4] << std::endl;
return 0;
}