測試類：

public?class?Initail?{
????public?static?void?main(String[]?args)?{
????????Phone?phone?=?new?Phone();
????????SmartPhone?smartPhone?=?new?SmartPhone();

????????phone.call();
????????smartPhone.call();

????????phone.printTarget();
????????smartPhone.printTarget();
????}
}

父類

public?class?Phone?{
????String?target?=?"me";
????public?void?call(){
????????System.out.println("You?call?to?"+this.target);
????}
????public?void?printTarget(){
????????System.out.println(this.target);
????}
}

子類

public?class?SmartPhone?extends?Phone?{
????//String?target?=?"notme";
????//不寫這一行，this.target?為父類中的me
????public?void?call(){
????????System.out.println("You?call?to?"+this.target);
????}
????public?void?printTarget(){
????????System.out.println(this.target);
????}
}

此時運行smartPhone.printTarget()的結果為me，在該類里沒有target變量，它卻識別到了父類里的target，但如果去掉注釋，他就會使用子類的target，這算是一種重寫嗎？按理說不可以定義重名的變量，那么是重寫了(子類有target變量，被覆寫為notme)，還是說目前的子類中沒有target變量，變量是父類的呢？（類似于子類沒有target存在時，target 就相當于是 super.target）