老師的代碼沒有問題，有相同錯誤的自己糾正。查看

private?Response?invokeRemote(Request?request)?{
????Response?resp?=?null;
????TransportClient?client?=?null;
????try?{
????????client?=?selector.select();
????????byte[]?outBytes??=?encoder.encode(request);
????????InputStream?receive?=?client.write(new?ByteArrayInputStream(outBytes));
????????byte[]?inBytes?=?IOUtils.readFully(receive,?receive.available());
????????resp?=?decoder.decode(inBytes,?Response.class);

????}?catch?(IOException?e)?{
????????log.warn(e.getMessage(),?e);
????????resp?=?new?Response();
????????resp.setCode(1);
????????resp.setMessage("RpcClient?got?error:"
????????+?e.getClass()
????????+?":"?+?e.getMessage());

????}?finally?{
????????if(client?!=?null){
????????????selector.release(client);
????????}
????}
????return?resp;
}

這部分代碼是否有誤。祝大家秋招順利～

看下RemoteInvoke.invoke是否有返回數據，就是在最后一步的時候不要return null;

因為老師的代碼實現有bug

RandomTransportSelector#select?方法實現錯誤，是取不應該是刪除；

可以直接clone我的代碼，可以直接運行出RPC效果

https://github.com/WuTong111/RPC.git

解決了嗎? ，同樣這個問題?