virtual 確實阻止了參數的傳遞。

但是你回到封裝的思想，一般都并不是在構造函數里面完成參數的傳遞，

而是通過 getter()、setter()函數，因此在第一層的父類Person中定義public的getter、setter函數即可，我試過了，孫子類可以直接跳過virtual定義的中間類，調用爺爺Person的getter、setter函數

//如果不用默認值，需要從子類的構造函數的初始化列表中傳給父類相應的參數，如下：
#include?<iostream>
#include?<string>
using?namespace?std;
class?Persion
{
public:????
????Persion(string?color?/*=?"red"*/):m_strColor(color){}
????void?play(){cout<<m_strColor<<endl;}
protected:	
????string?m_strColor;
};
class?Worker:virtual?public?Persion
{
public:
????Worker(int?salary,?string?color?=?"yellow"):Persion(color),m_iSalary(salary){}
protected:	
????int?m_iSalary;
};
class?Children:virtual?public?Persion
{
public:	
????Children(int?age,string?color?=?"green"):Persion(color),m_iAge(age){}
protected:	
????int?m_iAge;
};
class?ChildLabourer:public?Worker,public?Children
{
public:	ChildLabourer(int?age,?int?salary,?string?color):
????????Worker(salary,color),Children(age,color),Persion(color)
????????{
????????}
};
int?main()?
{	
????ChildLabourer?cl(10,1000,"black");
????cl.play();
????cl.Worker::play();
????cl.Children::play();
????cl.Worker::Persion::play();
????cl.Children::Persion::play();
????cl.Persion::play();
}