#include <stdio.h>
int main()
{
??? /* 定義需要計算的日期 */
??? int year = 2008;
??? int month = 8;
??? int day = 8;
??? int sum=0,a=0;
??? /*
???? * 請使用switch語句，if...else語句完成本題
???? * 如有想看小編思路的，可以點擊左側任務中的“不會了怎么辦”
???? * 小編還是希望大家獨立完成哦~
???? */
??? if(year%4==0)
??? {
??????? switch(month)
??????? {
??????????? case 1:sum=0;break;
??????????? case 2:sum=31;break;
??????????? case 3:sum=29+31;break;
??????????? case 4:sum=29+31+31;break;
??????????? case 5:sum=29+31+31+30;break;
??????????? case 6:sum=29+92+31;break;
??????????? case 7:sum=29+92+31+30;break;
??????????? case 8:sum=29+92+61+31;break;
??????????? case 9:sum=29+92+92+31;break;
??????????? case 10:sum=29+92+92+31+30;break;
??????????? case 11:sum=29+92+92+92;break;
??????????? case 12:sum=29+92+92+92+30;break;
??????? }
??????? a=sum+day;
??? }
??? else
???? switch(month)
??????? {
??????????? case 1:sum=0;break;
??????????? case 2:sum=31;break;
??????????? case 3:sum=30+31;break;
??????????? case 4:sum=30+31+31;break;
??????????? case 5:sum=30+31+31+30;break;
??????????? case 6:sum=30+92+31;break;
??????????? case 7:sum=30+92+31+30;break;
??????????? case 8:sum=30+92+61+31;break;
??????????? case 9:sum=30+92+92+31;break;
??????????? case 10:sum=30+92+92+31+30;break;
??????????? case 11:sum=30+92+92+92;break;
??????????? case 12:sum=30+92+92+92+30;break;
??????? }
??????? a=sum+day;
???
??? printf("\n2008年8月8日是該年第%d天",a);
???

?return 0;
}