在pycharm里寫吧。還有沒考慮判別式為負數的情況。

import?math
def?quadratic_equation2(a,?b,?c):
????pan?=?b?*?b?-?4?*?a?*?c
????if?pan?>=?0:
????????x1?=?(-b?+?math.sqrt(pan))?/?2?/?a
????????x2?=?(-b?-?math.sqrt(pan))?/?2?/?a
????else:
????????x1?=?str((-b)?/?2?/?a)?+?'+'?+?str(math.sqrt(-pan)?/?2?/?a)?+?'i'
????????x2?=?str((-b)?/?2?/?a)?+?'-'?+?str(math.sqrt(-pan)?/?2?/?a)?+?'i'
????return?x1,?x2

>>> import math
>>> def quadratic_equation(a, b, c):
...???? t = math.sqrt(b * b - 4 * a * c)
...???? return (-b + t) / (2 * a),( -b - t )/ (2 * a)
...
>>> print (quadratic_equation(2, 3, 0))
(0.0, -1.5)
>>> print (quadratic_equation(1, -6, 5))
(5.0, 1.0)
>>>

縮進的問題么

>>> import math
>>> def quadratic_equation(a, b, c):
...???? t = math.sqrt(b * b - 4 * a * c)
...???? return (-b + t) / (2 * a),( -b - t )/ (2 * a)
...???? print quadratic_equation(2, 3, 0)
...???? print quadratic_equation(1, -6, 5)

>>>
>>>
>>>
>>>
>>>

一直回車，出不來答案

你得吧代碼貼上，不然怎么回答