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幫忙看一下代碼的問題

public class QiChe {

private String name;//車名

private int pnum;//載客

private int hnum;//載人

private int price;//租金

public QiChe(String name, int pnum, int hnum, int price) {

super();

this.name = name;

this.pnum = pnum;

this.hnum = hnum;

this.price = price;

}

public String getName() {

return name;

}

public void setName(String name) {

this.name = name;

}


public int getPnum() {

return pnum;

}

public void setPnum(int pnum) {

this.pnum = pnum;

}

public int getHnum() {

return hnum;

}

public void setHnum(int hnum) {

this.hnum = hnum;

}

public int getPrice() {

return price;

}

public void setPrice(int price) {

this.price = price;

}

public int? sumPirce(int amounts ,int days) {

return amounts*days*price ;

}

}

//子類卡車

public class Trunk extends QiChe{

public Trunk(String name,int pnum,int hnum,int price) {

super(name, pnum, hnum, price);

}

}

//子類小車

public class Car extends QiChe{


public Car(String name, int pnum, int hnum, int price) {

super(name, pnum, hnum, price);

// TODO Auto-generated constructor stub

}

}

//子類皮卡

public class PickUp extends QiChe {


public PickUp(String name, int pnum, int hnum, int price) {

super(name, pnum, hnum, price);

// TODO Auto-generated constructor stub

}


}

//用戶使用

import java.util.Scanner;


public class Use {


public static void main(String[] args) {

// TODO Auto-generated method stub

//首先設置車的數據 用對象數組存放

QiChe[] trunks = {new Trunk("豐田貨車",0,20,500),new Trunk("暴龍貨車",0,10,300),new Trunk("貨拉拉",0,8,200)};

QiChe[] cars = {new Car("奧迪A6",8,0,1000),new Car("布加迪威龍",2,0,1500),new Car("一汽大眾",5,0,300)};

QiChe[] pickups = {new PickUp("不知道",2,5,300),new PickUp("叫什么",2,8,500),new PickUp("名字",4,10,800)};

System.out.println("welcome to DIDA");

System.out.println("plese choose some type of vehical to use");

System.out.println("請選擇:1只載人 2.只拉貨 3.拉貨且載人 ");

Scanner in1 = new Scanner(System.in);

int input1 = in1.nextInt();

switch(input1) {

case 1:

for(int i= 0;i<trunks.length;i++) {

System.out.println("編號"+i+"車型:"+trunks[i].getName()+" 載人數:"+trunks[i].getPnum()+" 載貨數:"+trunks[i].getHnum()+" 租金單日:"+trunks[i].getPrice());

}

break;

case 2:

for(int i= 0;i<cars.length;i++) {

System.out.println("編號"+i+"車型:"+cars[i].getName()+" 載人數:"+cars[i].getPnum()+" 載貨數:"+cars[i].getHnum()+" 租金單日:"+cars[i].getPrice());

}

break;

case 3:

for(int i= 0;i<pickups.length;i++) {

System.out.println("編號"+i+"車型:"+pickups[i].getName()+" 載人數:"+pickups[i].getPnum()+" 載貨數:"+pickups[i].getHnum()+" 租金單日:"+pickups[i].getPrice());

}

break;

default:System.out.println("請求失敗,請重新輸入");

}

System.out.println("請輸入車輛編號,租車天數,租車數量");

Scanner in2 = new Scanner(System.in);

int k = in2.nextInt();

Scanner in3 = new Scanner(System.in);

int m = in3.nextInt();

Scanner in4 = new Scanner(System.in);

int n = in4.nextInt();

if(input1 ==1) {

QiChe rent = trunks[k];

System.out.print("車型為"+rent.getName());

System.out.println("租金"+rent.getPrice()+"天數"+m+"車數"+n+"總金額為:"+rent.sumPirce(m, n));

}else if (input1 ==2) {

QiChe rent = cars[k];

System.out.print("車型為"+rent.getName());

System.out.println("租金"+rent.getPrice()+"天數"+m+"車數"+n+"總金額為:"+rent.sumPirce(m, n));

}else if(input1 ==3) {

QiChe rent = pickups[k];

System.out.print("車型為"+rent.getName());

System.out.println("租金"+rent.getPrice()+"天數"+m+"車數"+n+"總金額為:"+rent.sumPirce(m, n));

}else {

System.out.println("沒有此選項");

}

}

}

https://img1.sycdn.imooc.com//5c8de6e80001f6e604290342.jpg

正在回答

3 回答

載人對應case是1,是car吧;載貨對應case是2,是是trunks吧

0 回復 有任何疑惑可以回復我~

結果沒什么,但是那個switch不要寫default,因為你的default會導致程序繼續往下執行,而不會向你輸出的那樣重新輸入.還有碰到input.next()的時候程序應該會停止等待用戶輸入,所以你只要new一次Scanner就可以了,不需要new那么多次.

0 回復 有任何疑惑可以回復我~

載人對應case是1,是car吧;載貨對應case是2,是是trunks吧

0 回復 有任何疑惑可以回復我~

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幫忙看一下代碼的問題

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