#include <stdio.h>
int main()
{
?/* 定義需要計算的日期 */
?int year = 2008;
?int month = 8;
?int day = 8;
?/*
? * 請使用switch語句，if...else語句完成本題
? * 如有想看小編思路的，可以點擊左側任務中的“不會了怎么辦”
? * 小編還是希望大家獨立完成哦~
? */
?int m, sum;
?if ((year % 400 == 0) || (year % 4 == 0) && (year % 100 != 0)) {
??m = 29;
?}
?else {
??m = 28;
?}
?switch (month) {
?case 1: sum = day; break;
?case 2: sum = day + m; break;
?case 3: sum = day + m + 31; break;
?case 4: sum = day + m + 31 + 30; break;
?case 5: sum = day + m + 31 + 30 + 31; break;
?case 6: sum = day + m + 31 + 30 + 31 + 30; break;
?case 7: sum = day + m + 31 + 30 + 31 + 30 + 31; break;
?case 8: sum = day + m + 31 + 30 + 31 + 30 + 31 + 31; break;
?case 9: sum = day + m + 31 + 30 + 31 + 30 + 31 + 31 + 30; break;
?case 10: sum = day + m + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31; break;
?case 11: sum = day + m + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30; break;
?case 12: sum = day + m + 31 + 30 + 31 + 30 + 31 + 31 + 30 + 31 + 30 + 31; break;
?default: printf("一年有十二個月");
?}

?printf("計算%d年%d月%d日這一天，是該年中的第%d天", year, month, day, sum);

?getchar();
?getchar();

?return 0;
}