如何讓遞歸多次大循環 就比如求1！+2！+3！+4！+5！ 求完5！后讓n-1 再求4的階乘
#include<stdio.h>
int f(int n)
{
??? int result=0;
??? if(n==0 || n==1)
??? {
???? result = 1;
??? }
??? else
??? {??
????? result= f(n-1)*n;
??? }
??? return result;
}
int main()
{
????? int n;
?? scanf("%d",&n);
????? printf( "%d\n", f(n));
?? return 0;
}
2018-11-15
#include<stdio.h> int?f(int?n) { ????int?result=0; ????if(n==0?||?n==1) ????{ ?????result?=?1; ????} ????else ????{?? ??????result=?f(n-1)*n; ????} ????return?result; } int?main(){ int?n,i; scanf("%d",&n); for(i=1;i<=n;i++){ printf("%d\n",f(n)); return?0; } }