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運行正確,但是數據庫不能建表

//girl
package?com.example.demo;
import?javax.persistence.Entity;
import?javax.persistence.GeneratedValue;
import?javax.persistence.Id;

@Entity
public?class?girl?{
@Id
@GeneratedValue
????private?Integer?id;
????private?String?cupSize;
????private?Integer?age;

????public?girl()?{
????}

????public?Integer?getId()?{
????????return?id;
????}

????public?void?setId(Integer?id)?{
????????this.id?=?id;
????}

????public?String?getCupSize()?{
????????return?cupSize;
????}

????public?void?setCupSize(String?cupSize)?{
????????this.cupSize?=?cupSize;
????}

????public?Integer?getAge()?{
????????return?age;
????}

????public?void?setAge(Integer?age)?{
????????this.age?=?age;
????}
}

//Girlproperties

package?com.example.demo;

import?org.springframework.boot.context.properties.ConfigurationProperties;
import?org.springframework.stereotype.Component;

@Component
@ConfigurationProperties(prefix?=?"girl")
public?class?Girlproperties?{
????private?String?cupSize;
????private?Integer?age;

????public?String?getCupSize()?{
????????return?cupSize;
????}

????public?void?setCupSize(String?cupSize)?{
????????this.cupSize?=?cupSize;
????}

????public?Integer?getAge()?{
????????return?age;
????}

????public?void?setAge(Integer?age)?{
????????this.age?=?age;
????}
}


正在回答

1 回答

啟動類不要寫

@SpringBootApplication(exclude?=?DataSourceAutoConfiguration.class)

直接改成

@SpringBootApplication


0 回復 有任何疑惑可以回復我~

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運行正確,但是數據庫不能建表

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