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print [a*100+b*10+a for a in range(1,10) for b in range(0,10)]
2018-09-19
源自：初識Python 10-4
正在回答
少了一層循環，方法新穎，贊
我想問，這個有問題吧！
你的代碼應該是跟我的代碼一樣的吧
L=[]
for a in range(1,10):
? ? for b in range(0,10):
? ? ? ? for a in range(1,10):
? ? ? ? ? ? L.append(a*100+b*10+a)
print L
這樣的結果是錯誤的，重復了很多遍！
[101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, 848, 949, 151, 252, 353, 454, 555, 656, 757, 858, 959, 161, 262, 363, 464, 565, 666, 767, 868, 969, 171, 272, 373, 474, 575, 676, 777, 878, 979, 181, 282, 383, 484, 585, 686, 787, 888, 989, 191, 292, 393, 494, 595, 696, 797, 898, 999, 101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, 848, 949, 151, 252, 353, 454, 555, 656, 757, 858, 959, 161, 262, 363, 464, 565, 666, 767, 868, 969, 171, 272, 373, 474, 575, 676, 777, 878, 979, 181, 282, 383, 484, 585, 686, 787, 888, 989, 191, 292, 393, 494, 595, 696, 797, 898, 999, 101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, 848, 949, 151, 252, 353, 454, 555, 656, 757, 858, 959, 161, 262, 363, 464, 565, 666, 767, 868, 969, 171, 272, 373, 474, 575, 676, 777, 878, 979, 181, 282, 383, 484, 585, 686, 787, 888, 989, 191, 292, 393, 494, 595, 696, 797, 898, 999, 101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, 848, 949, 151, 252, 353, 454, 555, 656, 757, 858, 959, 161, 262, 363, 464, 565, 666, 767, 868, 969, 171, 272, 373, 474, 575, 676, 777, 878, 979, 181, 282, 383, 484, 585, 686, 787, 888, 989, 191, 292, 393, 494, 595, 696, 797, 898, 999, 101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, 848, 949, 151, 252, 353, 454, 555, 656, 757, 858, 959, 161, 262, 363, 464, 565, 666, 767, 868, 969, 171, 272, 373, 474, 575, 676, 777, 878, 979, 181, 282, 383, 484, 585, 686, 787, 888, 989, 191, 292, 393, 494, 595, 696, 797, 898, 999, 101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, ...........不復制了
慕粉3943801
方法很棒
時間復雜度更好，不過稍微有點問題，個位數的取值是0-9，而樓主a的取值是1-9
qq_慕蓋茨6588993
牛逼牛逼牛逼
print[a for a in range(100,1000) if int(a%1000/100)==a%10]
好好好
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2018-09-20
少了一層循環，方法新穎，贊
2019-05-29
我想問，這個有問題吧！
你的代碼應該是跟我的代碼一樣的吧
L=[]
for a in range(1,10):
? ? for b in range(0,10):
? ? ? ? for a in range(1,10):
? ? ? ? ? ? L.append(a*100+b*10+a)
print L
這樣的結果是錯誤的，重復了很多遍！
[101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, 848, 949, 151, 252, 353, 454, 555, 656, 757, 858, 959, 161, 262, 363, 464, 565, 666, 767, 868, 969, 171, 272, 373, 474, 575, 676, 777, 878, 979, 181, 282, 383, 484, 585, 686, 787, 888, 989, 191, 292, 393, 494, 595, 696, 797, 898, 999, 101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, 848, 949, 151, 252, 353, 454, 555, 656, 757, 858, 959, 161, 262, 363, 464, 565, 666, 767, 868, 969, 171, 272, 373, 474, 575, 676, 777, 878, 979, 181, 282, 383, 484, 585, 686, 787, 888, 989, 191, 292, 393, 494, 595, 696, 797, 898, 999, 101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, 848, 949, 151, 252, 353, 454, 555, 656, 757, 858, 959, 161, 262, 363, 464, 565, 666, 767, 868, 969, 171, 272, 373, 474, 575, 676, 777, 878, 979, 181, 282, 383, 484, 585, 686, 787, 888, 989, 191, 292, 393, 494, 595, 696, 797, 898, 999, 101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, 848, 949, 151, 252, 353, 454, 555, 656, 757, 858, 959, 161, 262, 363, 464, 565, 666, 767, 868, 969, 171, 272, 373, 474, 575, 676, 777, 878, 979, 181, 282, 383, 484, 585, 686, 787, 888, 989, 191, 292, 393, 494, 595, 696, 797, 898, 999, 101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, 848, 949, 151, 252, 353, 454, 555, 656, 757, 858, 959, 161, 262, 363, 464, 565, 666, 767, 868, 969, 171, 272, 373, 474, 575, 676, 777, 878, 979, 181, 282, 383, 484, 585, 686, 787, 888, 989, 191, 292, 393, 494, 595, 696, 797, 898, 999, 101, 202, 303, 404, 505, 606, 707, 808, 909, 111, 212, 313, 414, 515, 616, 717, 818, 919, 121, 222, 323, 424, 525, 626, 727, 828, 929, 131, 232, 333, 434, 535, 636, 737, 838, 939, 141, 242, 343, 444, 545, 646, 747, ...........不復制了
2019-04-22
方法很棒
2019-01-27
時間復雜度更好，不過稍微有點問題，個位數的取值是0-9，而樓主a的取值是1-9
2018-12-09
牛逼牛逼牛逼
2018-09-20
print[a for a in range(100,1000) if int(a%1000/100)==a%10]
2018-09-19
好好好