請?？歼@個！

判斷是不是閏年就行啦

#include <stdio.h>
int main()
{
??? /* 定義需要計算的日期 */
??? int year = 2008;
??? int month = 8;
??? int day = 8;
??? int i,num;//i用來表示2月的28天是否該加一,num表示和
??? if((year%400==0&&year%100==0)||year%4==0)//判定是否是閏年
??????? i=1;
??? else
??????? i=0;
??? switch(month)
?????? {
??????? case 1:num=i+day;break;
??????? case 2:num=i+day+31;break;
??????? case 3:num=i+day+31+28;break;
??????? case 4:num=i+day+31+28+31;break;
??????? case 5:num=i+day+31+28+31+30;break;
??????? case 6:num=i+day+31+28+31+30+31;break;
??????? case 7:num=i+day+31+28+31+30+31+30;break;
??????? case 8:num=i+day+31+28+31+30+31+30+31;break;
??????? case 9:num=i+day+31+28+31+30+31+30+31+31;break;
??????? case 10:num=i+day+31+28+31+30+31+30+31+31+30;break;
??????? case 11:num=i+day+31+28+31+30+31+30+31+31+30+31;break;
??????? case 12:num=i+day+31+28+31+30+31+30+31+31+30+31+30;break;
?????? }
??? printf("%d年%d月%d日是該年的第%d天",year,month,day,num);
?return 0;
}