def?square_of_sum(L):
????L=[]
????sum=0
????for?x?in?L:
????????sum=sum+pow(x,2)
????return?sum
print?square_of_sum([1,?2,?3,?4,?5])
print?square_of_sum([-5,?0,?5,?15,?25]

1.運行結果是：0,0

def?square_of_sum(L):
????for?x?in?L:
????????y=pow(x,2)
????return?sum(y)
print?square_of_sum([1,?2,?3,?4,?5])
print?square_of_sum([-5,?0,?5,?15,?25])

2.這個運行錯誤，應該怎么改呢？

def?square_of_sum(L):
????for?x?in?L:
????return?sum(pow(x,2))
print?square_of_sum([1,?2,?3,?4,?5])
print?square_of_sum([-5,?0,?5,?15,?25])

3.這個也是運行錯誤，我查了下，for x in L：之后必須加內容，但是如何不加內容來表示x在L里呢？