這樣寫是不是繞路了
public class HelloWorld{
? ? public static void main(String[] args) {
? ? int one = 10 ;
? ? ? ? int two = 20 ;
? ? ? ? int three = 0 ;
? ? ? ? int aa= one + two;
? ? ? ? int bb= (three+=one);
? ? ? ? int cc= (three-=one);
? ? ? ? int dd= (three*=one);
? ? ? ? int ee= (three/=one);
? ? ? ? int ff= (three%=one);
? ? ? ? System.out.println("three = one + two==>" +aa);
? ? ? ? System.out.println("three += one ==>" +bb);
? ? ? ? System.out.println("three -= one ==>" +cc);
? ? ? ? System.out.println("three *= one ==>" +dd);
? ? ? ? System.out.println("three /= one ==>" +ee);
? ? ? ? System.out.println("three %= one ==>" +ff);
}
}
2018-07-12
你這樣是錯的，賦值運算符計算后是會賦值的，會把計算的值賦給three，你只有后面的three值一直都沒變，與題意不符，題意是每運算一次賦值給three，然后進行下一次運算
2018-07-12
System.out.println("three=one + two ==>"+(three=one + two));
? ? ? ? System.out.println("three+=one ==>"+(three+=one));
? ? ? ? System.out.println("three-=one ==>"+(three-=one));
? ? ? ? System.out.println("three*=one ==>"+(three*=one));
? ? ? ? System.out.println("three/=one ==>"+(three/=one));
? ? ? ? System.out.println("three%=one ==>"+(three%=one));
??