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for循環拋出異常

<%@ page language="java" import="java.util.*" contentType="text/html; charset=UTF-8"

? ? pageEncoding="UTF-8"%>

<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">

<html>

<head>

<meta http-equiv="Content-Type" content="text/html; charset=UTF-8">

<title>Insert title here</title>

</head>

<body>

<h1>request內置對象</h1>

<%

? request.setCharacterEncoding("utf-8");

%>

?用戶名:<%=request.getParameter("usename") %><br>

?愛好:<%?

?String[] favorites=request.getParameterValues("favorite");?

?for(int i=0;i<favorites.length;i++)

?{

out.println(favorites[i]+"&nbsp;&nbsp;&nbsp;&nbsp;");

?}

?%>

</body>

</html>



HTTP Status 500 – Internal Server Error


Type Exception Report

Message An exception occurred processing JSP page [/request.jsp] at line [14]

Description The server encountered an unexpected condition that prevented it from fulfilling the request.

Exception

org.apache.jasper.JasperException:?An?exception?occurred?processing?JSP?page?[/request.jsp]?at?line?[14]

11:??用戶名:<%=request.getParameter("usename")?%><br>
12:??愛好:<%?
13:??String[]?favorites=request.getParameterValues("favorite");?
14:??for(int?i=0;i<favorites.length;i++)
15:??{
16:?	?out.println(favorites[i]+"&nbsp;&nbsp;&nbsp;&nbsp;");
17:??}


Stacktrace:
	org.apache.jasper.servlet.JspServletWrapper.handleJspException(JspServletWrapper.java:584)
	org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:481)
	org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:386)
	org.apache.jasper.servlet.JspServlet.service(JspServlet.java:330)
	javax.servlet.http.HttpServlet.service(HttpServlet.java:742)
	org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)

Root Cause

java.lang.NullPointerException
	org.apache.jsp.request_jsp._jspService(request_jsp.java:126)
	org.apache.jasper.runtime.HttpJspBase.service(HttpJspBase.java:70)
	javax.servlet.http.HttpServlet.service(HttpServlet.java:742)
	org.apache.jasper.servlet.JspServletWrapper.service(JspServletWrapper.java:443)
	org.apache.jasper.servlet.JspServlet.serviceJspFile(JspServlet.java:386)
	org.apache.jasper.servlet.JspServlet.service(JspServlet.java:330)
	javax.servlet.http.HttpServlet.service(HttpServlet.java:742)
	org.apache.tomcat.websocket.server.WsFilter.doFilter(WsFilter.java:52)

Note The full stack trace of the root cause is available in the server logs.


Apache Tomcat/8.0.0


正在回答

4 回答

你的上一個跳轉頁面有信息沒有填,造成空指針異常,

空指針異常不能捕捉,解決方法就是將容易為空的字段加上非空判斷,阻止此字段為空時運行代碼造成報錯。

1 回復 有任何疑惑可以回復我~
加一句判斷非空?if(request.getparameterValues(favorite)!=null)
?{
????String[]?favorites=request.getParameterValues("favorite");?
??????for(int?i=0;i<favorites.length;i++)
??????{
????????out.println(favorites[i]+"&nbsp;&nbsp;&nbsp;&nbsp;");
??????}
?
?}
0 回復 有任何疑惑可以回復我~
favorite和表單里用的name名稱一樣嗎
0 回復 有任何疑惑可以回復我~
favorites可能為空,先用if判斷一下是否為空


1 回復 有任何疑惑可以回復我~

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