加了個循環，可以不？

#include <stdio.h>
int main()
{
??? /* 定義需要計算的日期 */
??? int year = 2008;
??? int month = 8;
??? int day = 8;
??? /*
???? * 請使用switch語句，if...else語句完成本題
???? * 如有想看小編思路的，可以點擊左側任務中的“不會了怎么辦”
???? * 小編還是希望大家獨立完成哦~
???? */
??? int sum=0;
??? int i;
??? int advance=month-1;
??? for(i=1;i<=advance;i++){
??????? switch(i){
??????? case 1:
??????? case 3:
??????? case 5:
??????? case 7:
??????? case 8:
??????? case 10:
??????? case 12:
??????????? sum+=31;
??????????? break;
??????? case 2:
??????????? if(year%4==0&&year%100!=0||year%400==0){
??????????????? sum+=29;
??????????? }else{
??????????????? sum+=28;
??????????? }
??????????? break;
??????? default:
??????????? sum+=30;
??????????? break;
??? }
?? ?
??? }
??? sum+=day;
?? ?
??? printf("2008年8月8日是該年的第%d天",sum);

?? ?return 0;
}

教練我要學習

2018-07-01

源自：C語言入門 4-17

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3 回答

kirito_yes
2018-07-03

#include?<stdio.h>
int?main(){	
????int?year?=?2008;	???
????int?month?=?8;	
????int?day?=?8;	
????int?sum?=?0;	
????int?i;	
????for?(i?=?1;?i<month;?i++)?{		
????????switch?(i)?{		
????????????case?1:		
????????????case?3:		
????????????case?5:		
????????????case?7:		
????????????case?8:		
????????????case?10:		
????????????case?12:			
????????????????sum?+=?31;			
????????????????break;		
????????????case?4:		
????????????case?6:		
????????????case?9:		
????????????case?11:			
????????????????sum?+=?30;			
????????????????break;		
????????????case?2:			
????????????????sum?+=?(year?%?4?&&?year?%?100?!=?0?||?year?%?400?==?0)???28?:?29;		
?????????}	
?????}	
??????sum?+=?day;
??????printf("%d年%d月%d日是該年的第%d天\n",?year,?month,?day,?sum);	
??????return?0;
}