regex 問題
請問怎樣寫可以從下面取出 https://images-na.ssl-images-amazon.com/images/I/51e79yXDDlL.jpg
(注意是不要._SS40)
<span><span><input /><span><img src="https://images-na.ssl-images-amazon.com/images/I/51e79yXDDlL._SS40_.jpg" /></span></span></span>
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2018-06-26
<?php
$pattern='/https?:.+\.jpg/';
$subject='<span><span><input /><span><img src="https://images-na.ssl-images-amazon.com/images/I/51e79yXDDlL._SS40_.jpg" /></span></span></span>';
$arr=array();
$url;
preg_match($pattern,$subject,$arr);
$url=str_replace("._SS40_","",$arr[0]);
echo $url;
?>