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數列表達式s=1+1/2+1/3+1/4+……+1/n,當n=10時,求s的近似值。
2018-03-08
源自:C語言入門 4-2
正在回答
//超簡版 float?add(int?a){ ????float?sum=0; ????for(float?i=1.0;i<=10.0;i++){ ????????sum+=1/i; ????} ????return?sum; } int?main() { ????printf("%f\n",add(10)); ????return?0; }
簡化版
int a();?{??float sum = 0;??int?i=0;??float a[10] = { 1,2,3,4,5,6,7,8,9,10 };??while( i <= 9)??{???a[i] = 1 / a[i];???sum += a[i];???i++;??}??//printf("%1.0f", sum);//輸出整數??printf("%1.6f", sum);//輸出小數點后六位?}
int a();??{???float sum = 0;???float a[10] = { 1,2,3,4,5,6,7,8,9,10 };???for (int i = 0; i <= 9; i++)???{????a[i] = 1/a[i] ;???}??????for (int i = 0; i < 10; i++)???{????printf("%1.6f\n", a[i]);//遍歷數組????sum += a[i];???}???//printf("%1.0f", sum);//輸出整數???printf("%1.6f", sum);//輸出小數點后六位??}
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2018-03-10
2018-03-09
簡化版
int a();
?{
??float sum = 0;
??int?i=0;
??float a[10] = { 1,2,3,4,5,6,7,8,9,10 };
??while( i <= 9)
??{
???a[i] = 1 / a[i];
???sum += a[i];
???i++;
??}
??//printf("%1.0f", sum);//輸出整數
??printf("%1.6f", sum);//輸出小數點后六位
?}
2018-03-09
int a();
??{
???float sum = 0;
???float a[10] = { 1,2,3,4,5,6,7,8,9,10 };
???for (int i = 0; i <= 9; i++)
???{
????a[i] = 1/a[i] ;
???}
???
???for (int i = 0; i < 10; i++)
???{
????printf("%1.6f\n", a[i]);//遍歷數組
????sum += a[i];
???}
???//printf("%1.0f", sum);//輸出整數
???printf("%1.6f", sum);//輸出小數點后六位
??}