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                        /JAVA遇見HTML——Servlet篇

這個該怎么辦好呢？

<%@?page?contentType="text/html;charset=UTF-8"?language="java"?%>
<html>
<head>
????<title>Test</title>
</head>
<body>
<form?action="com/servlet/LoginServlet"?method="post">
????<table>
????????<tr>
????????????<td>用戶名：</td>
????????????<td><input?type="text"?name="username"></td>
????????</tr>
????????<tr>
????????????<td>密碼：</td>
????????????<td><input?type="password"?name="password"></td>
????????</tr>
????????<td>
????????????<td><input?type="submit"?value="登錄"?/></td>
????????</tr>
????</table>
</form>
</body>
</html>

<%@?page?contentType="text/html;charset=UTF-8"?language="java"?%>
<html>
<head>
????<title>LoginSuccess</title>
</head>
<body>
<h1>登錄成功！</h1>
<jsp:useBean?id="loginuser"?class="com.entity.User"?scope="session"?/><br>
歡迎您，<jsp:getProperty?name="loginuser"?property="username">!<br>
</body>
</html>

@WebServlet(name?=?"LoginServlet")
public?class?LoginServlet?extends?HttpServlet?{
????protected?void?doPost(HttpServletRequest?request,?HttpServletResponse?response)?throws?ServletException,?IOException?{
????????request.setCharacterEncoding("utf-8");
????????String?username?=?request.getParameter("username");
????????String?password?=?request.getParameter("password");
????????User?user?=?new?User();
????????user.setUsername(username);
????????user.setUsername(password);
????????request.getSession().setAttribute("loginuser",user);
????????if(username.equals("admin")&&password.equals("admin")){
????????????response.sendRedirect(request.getContextPath()+"/loginSuccess.jsp");
????????}
????}

????protected?void?doGet(HttpServletRequest?request,?HttpServletResponse?response)?throws?ServletException,?IOException?{
????????doPost(request,response);
????}
}

為什么我這登錄頁面總是跳轉不到成功頁面呢？

但是系統總是報這行代碼錯誤：

<jsp:getProperty name="loginuser" property="username">