為什么不能用$(this)
如果用$(this).name就會返回undefined,如果用this.name就正常顯示,這是為何?
<!DOCTYPE?html>
<html>
????<head>
????????<meta?http-equiv="Content-Type"?content="text/html;?charset=utf-8"?/>
????????<title>挑戰題</title>
????????<script?type="text/javascript"?src="http://apps.bdimg.com/libs/jquery/2.1.4/jquery.min.js"></script>
????</head>
????<body>
????????<ul?id="result"?style="list-style:none"></ul>
????????<script?type="text/javascript">
????????$(document).ready(function(){
???????????var?json=[
????????????{"name":"小明","sex":"男","age":14,"married":false}
???????????,{"name":"小紅","sex":"女","age":11,"married":false}
???????????,{"name":"小剛","sex":"男","age":16,"married":true}
????????????????];
????????????$.each(json,function(index,e){
???????????????$("#result").append("<li>姓名:"+$(this).name+",性別:"+e.sex+",年齡:"+e.age+",已婚:"+e.married+"</li>");?
????????????});
????????});?????????
????????</script>?
????</body>
</html>
2017-09-04
$(this) 返回一個Jq對象
$(this)[0].name 就能訪問到name
2017-07-14
這里調用的是DOM對象啊，e就相當于this選擇器
2017-07-11
我說錯了,不好意思啊 , each中this和e相同,jquery內部處理的,你再把他處理成jquery以后就不能直接點語法訪問到name了
2017-07-11
each函數中this已經被jQuery處理過了,已經是jquery對象了