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                        /后端開發
                        
                            /Java
                        
                        /Java Web開發技術應用——過濾器

LoginServlet頁面404

@WebServlet(name="LoginServlet",?urlPatterns={"/LoginServlet"})
public?class?LoginServlet?extends?HttpServlet?{
	private?static?final?long?serialVersionUID?=?1L;
???????
????/**
?????*?@see?HttpServlet#HttpServlet()
?????*/
????public?LoginServlet()?{
????}
????
	/**
	?*?@see?HttpServlet#doPost(HttpServletRequest?request,?HttpServletResponse?response)
	?*/
	protected?void?doPost(HttpServletRequest?request,?HttpServletResponse?response)?throws?ServletException,?IOException?{
		System.out.println("doPost");
		String?username?=?request.getParameter("username");
		String?password?=?request.getParameter("password");
		System.out.println(request.getContextPath());
		if("admin".equals(username)?&&?"admin".equals(password))?{
			//校驗通過
			HttpSession?session?=?request.getSession();
			session.setAttribute("username",?username);
			System.out.println(request.getContextPath());
			response.sendRedirect(request.getContextPath()+?"/success.jsp");
		}else?{
			//校驗失敗
			response.sendRedirect(request.getContextPath()+?"/failure.jsp");
		}
	}

}

這是LoginServlet.java的代碼，輸入用戶名密碼后跳轉頁面出錯，404

<body>
	<form?action="<%=request.getContextPath()?%>/servlet/LoginServlet"?method="post">
		用戶名：<input?type="text"?name="username"?/>
		密碼：<input?type="password"?name="password"?/>
		<input?type="submit"?value="提交"?/>
	</form>
</body>

上面這是login.jsp的代碼

輸入用戶名密碼登錄以后，顯示頁面為：

HTTP?Status?404?-?/LoginFilter/servlet/LoginServlet
type?Status?report
message?/LoginFilter/servlet/LoginServlet
description?The?requested?resource?is?not?available.