判斷位數問題
判斷一個數（不僅是小于10位，還包括大于10位）的位數，例如輸入999999999999，則輸出“它是個12位的數”
慕標1993457
2017-02-19
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2017-02-19
package imooc.com;
import java.util.Scanner;
public class Demo3 {
public static void main(String[] args) {
Scanner input=new Scanner(System.in);
System.out.println("***請輸入一個判斷位的數***");
long num=input.nextLong();
long i=10;
long count=1;
while((num/i)!=0)
{
i*=10;
count++;
}
System.out.println("輸入實數位數為："+count);
}
}
2017-02-19
public?class?HelloWorld{
public?static?void?main(String[]?args){
long num?=?999999999999l;
int?count?=?0;
if(num>=0?){
????do{
????????count++;
????????num=num/10;
????}
????while?(num>0);
????System.out.println("它是個"+count+"位的數！");
????}
else
System.out.println("輸入數據錯誤");
}
}
? ?
2017-02-19
public class HelloWorld{
public static void main(String[] args){
long num = 999999999999l;
int count = 0;
do{
? ? count++;
? ? num=num/10;
}while(num>0);
System.out.println("它是個"+count+"位的數！");
}
}
2017-02-19
public?class?HelloWorld{ public?static?void?main(String[]?args){ long?int?num?=?999999999999; int?count?=?0; if(num>=0?){ ????do{ ????????count++; ????????num=num/10; ????} ????while?(num>0); ????System.out.println("它是個"+count+"位的數！"); ????} else System.out.println("輸入數據錯誤"); } }