1 回答#include <stdio.h> int main() { int x = 10; int y = 10; //使用簡單賦值語句實現x乘以2。 x=2*x; //使用復合賦值語句實現y乘以2。 y*=2; printf("x=%d\n", x); printf("y=%d\n", y); return 0; }

3 回答#include <stdio.h> int main() { int x = 10; int y = 10; //使用簡單賦值語句實現x乘以2。 //使用復合賦值語句實現y乘以2。 printf("x=x*2%d\n", x); printf("y*=2%d\n", y); return 0; }

4 回答#include <stdio.h> int main() { int x = 10; int y = 10； x=x*2; y*=2; printf("x=%d\n", x); printf("y=%d\n", y); return 0; }

2 回答include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;

2 回答#include <stdio.h> int main() { int x,y; x = 10; y = -3; printf("x+y=%d\n", x+y ); printf("x-y=%d\n", x-y ); printf("x*y=%d\n", x*y ); printf("x/y=%d\n", x/y ); printf("x%y=%d\n", x%y ); return 0;