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為什么校驗不通過也可以提交

我按照老師說的那么寫了之后 但是校驗不通過也可以提交數據給后臺???那這樣怎么行呢

?$("#signup").validate({
????????rules:{
????????????Username:{
????????????????required:true,
????????????????minlength:2
????????????},
????????????EmailAddress:{
????????????????required:true,
????????????????email:true
????????????},
????????????Password:{
????????????????required:true,
????????????????minlength:?6,
????????????????maxlength:?18
????????????}
????????},
????????messages:?{
????????????Username:?{
????????????????required:"請輸入用戶名",
????????????????minlength:"至少兩位"
????????????},
????????????EmailAddress:?{
????????????????required:"請輸入密碼",
????????????????email:"郵箱格式不對"
????????????},
????????????Password:{
????????????????required:true,
????????????????minlength:?"最少六位",
????????????????maxlength:?"最多18位"
????????????}
????????},
????????submitHandler:?function?(form)?{?//?for?demo
????????????alert('valid?form?submitted');?//?for?demo
????????????$("input[id=submit2]").click(function?()?{
????????????????event.preventDefault();
????????????????$.post("http://218.192.169.173/taobao/login.php",?{
????????????????????email:?$("#EmailAddress1").val(),
????????????????????password:?$("#PassWord").val()
????????????????},?function?(data,?textStatus)?{
????????????????????var?username?=?data.username;
????????????????????var?errnum?=?data.errno;
????????????????????alert(username);
????????????????},"json");
????????????});
????????????return?false;?//?for?demo
????????}
})
});

這是我的js代碼

正在回答

1 回答

會不會是提交按鈕(submit2)本身的設置,比如類型就是submit?

0 回復 有任何疑惑可以回復我~

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