def quadratic_equation(a, b, c):

??? if b**2 - 4*a*c > 0:
??????? m = (-b + (b**2 - 4*a*c)**1/2)*1/(2*a)
??????? n = (-b - (b**2 - 4*a*c)**1/2)*1/(2*a)
??? elif b**2 - 4*a*c == 0:
??????? m == n == -b/(2*a)
??? else:
??????? none
??? return m,n
print quadratic_equation(2.0, 3, 0)
print quadratic_equation(1.0, -6, 5)

import math

def quadratic_equation(a, b, c):

? ? m = 0.0

? ? n= 0.0

? ? if b**2 - 4*a*c > 0:

? ? ? ? m = (-b + (b**2 - 4*a*c)**1/2)*1/(2*a)

? ? ? ? n = (-b - (b**2 - 4*a*c)**1/2)*1/(2*a)

? ? elif b**2 - 4*a*c == 0:

? ? ? ? m == n == -b/(2*a)

? ? else:

? ? ? ? none

? ? return m,n

print (quadratic_equation(2, 3, 0))

print (quadratic_equation(1, -6, 5))

import?math

def?quadratic_equation(a,?b,?c):
????m?=?0.0
????n?=?0.0
????if?b**2?-?4*a*c?>?0:
????????m?=?(-b?+?(b**2?-?4*a*c)**1/2)*1.0/(2*a)??//關鍵是乘以1.0就可以做一次類型轉化了
????????n?=?(-b?-?(b**2?-?4*a*c)**1/2)*1.0/(2*a)??
????elif?b**2?-?4*a*c?==?0:
????????m?==?n?==?-b/(2*a)
????else:
????????none
????return?m,n

print?quadratic_equation(2,?3,?0)
print?quadratic_equation(1,?-6,?5)

import math

def quadratic(a, b, c):

? ? x1 = (-b + math.sqrt(b*b-4*a*c))/(2*a)

? ? x2 =(-b - math.sqrt(b*b-4*a*c))/(2*a)

? ? return x1,x2