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為什么照著打卻提示這種錯誤?

D:\Python\Python35-32\python.exe D:/111/Pytest/bstest.py

Traceback (most recent call last):

? File "D:/111/Pytest/bstest.py", line 17, in <module>

? ? soup = bs(html_doc,"html.parser")

? File "D:\Python\Python35-32\lib\site-packages\bs4\__init__.py", line 196, in __init__

? ? self._feed()

? File "D:\Python\Python35-32\lib\site-packages\bs4\__init__.py", line 210, in _feed

? ? self.builder.feed(self.markup)

? File "D:\Python\Python35-32\lib\site-packages\bs4\builder\_htmlparser.py", line 156, in feed

? ? parser = BeautifulSoupHTMLParser(*args, **kwargs)

TypeError: __init__() got an unexpected keyword argument 'strict'


Process finished with exit code 1

===========================================

我照著老師那樣打出現了這種錯誤提示,是哪里出了問題呢?下面是代碼:

from?bs4?import??BeautifulSoup?as?bs

html_doc?=?"""
<html><head><title>The?Dormouse's?story</title></head>
<body>
<p?class="title"><b>The?Dormouse's?story</b></p>

<p?class="story">Once?upon?a?time?there?were?three?little?sisters;?and?their?names?were
<a?>Elsie</a>,
<a?>Lacie</a>?and
<a?>Tillie</a>;
and?they?lived?at?the?bottom?of?a?well.</p>

<p?class="story">...</p>
"""

soup?=?bs(html_doc,"html.parser")

print(soup.prettify())


正在回答

1 回答

17行修改成 soup = bs(html_doc) 試一下還會報錯嗎

0 回復 有任何疑惑可以回復我~

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為什么照著打卻提示這種錯誤?

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