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sum = 0x = 1while x < 51:??? sum = sum + (2*x-1)print sum
2016-08-21
源自:初識Python 5-5
正在回答
少了x+1
zhusilun 提問者
sum = 0x = 1while x < 51:??? sum = sum + (2*x-1)
? ? x = x + 1print sum
x一直都是1,所以一直執行語句
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2016-08-21
sum = 0
x = 1
while x < 51:
??? sum = sum + (2*x-1)
print sum
少了x+1
2016-08-21
sum = 0
x = 1
while x < 51:
??? sum = sum + (2*x-1)
? ? x = x + 1
print sum
2016-08-21
x一直都是1,所以一直執行語句