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                        /Struts2攔截器淺析

報404錯誤并且控制臺毫無信息怎么辦？

我按照視頻中的在index.jsp中寫了一個超鏈接，href="timer"，然后寫了TimerAction，重寫了execute方法，最后在struts.xml中配置了，但是跳轉到success.jsp頁面的時候報了404錯誤并且控制臺沒有報錯信息，我該怎么追蹤呢？

<%@?page?language="java"?contentType="text/html;?charset=UTF-8"
????pageEncoding="UTF-8"%>
<!DOCTYPE?html?PUBLIC?"-//W3C//DTD?HTML?4.01?Transitional//EN"?"http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<meta?http-equiv="Content-Type"?content="text/html;?charset=UTF-8">
<title>Insert?title?here</title>
</head>
<body>
index，<a?href="timer">執行action并計算執行時間</a>
</body>
</html>

package?com.v3.action;

import?com.opensymphony.xwork2.ActionSupport;

public?class?TimerAction?extends?ActionSupport?{

????@Override
????public?String?execute()?throws?Exception?{
????????for(int?i=0;?i?<?10000;?i++){
????????????System.out.println("I?LOVE?V3");
????????}
????????return?SUCCESS;
????}
????
}

<?xml?version="1.0"?encoding="UTF-8"??>
<!DOCTYPE?struts?PUBLIC
????"-//Apache?Software?Foundation//DTD?Struts?Configuration?2.5//EN"
????"http://struts.apache.org/dtds/struts-2.5.dtd">


<struts>
????<package?name="default"?namespace="/"?extends="struts-default">
????????<action?name="timer"?class="com.v3.action.TimerAction">
????????????<result>/success.jsp</result>
????????</action>
????</package>
????
</struts>