import android.content.Context;

import android.database.sqlite.SQLiteDatabase;

import android.database.sqlite.SQLiteOpenHelper;

import android.database.sqlite.SQLiteDatabase.CursorFactory;

public ?class SqlHelp extends SQLiteOpenHelper{

String createUserTable = "create table user_info(_id int auto_increment,username char(20),"

+ "password char(20),num char(20),primary key('_id'));";

String createUserTable2 = "create table user_info1(_id int auto_increment,username char(20),"

+ "password char(20),num char(20),primary key('_id'));";

String insertStr = "insert into user_info(_id,username,password,num) values(?,?,?,?);";

public SqlHelp(Context context, String name, CursorFactory factory, int version)

{

super(context, name, factory, version);

// TODO 自動生成的構造函數存根

}

@Override

public void onCreate(SQLiteDatabase arg0)?

{

// TODO 自動生成的方法存根

int _id = 0;

arg0.execSQL(createUserTable);

arg0.execSQL(createUserTable2);

String[] insertValue = { "1", "hx", "123", "002", };

arg0.execSQL(insertStr, insertValue);

}

@Override

public void onUpgrade(SQLiteDatabase arg0, int arg1, int arg2) {

// TODO 自動生成的方法存根

}

}

使用這種方式插入和創建均不成功 在protected void onCreate(Bundle savedInstanceState)?

使用sDatabase.execSQL("insert into user_info(_id,username,password,num) values(0,'hxx',123,001);");則可以 求解