利用Collections.sort()方法對泛型為String的List進行排序 * 1.添加十條隨機字符串 * 2.每條字符串長度也是10以內的隨機長度 * 3.每條字符串的每個字符也都是隨機生成，字符可以重復 * 4.每條字符串不可以重復
??List<String>?stringList?=?new?ArrayList<String>();
????Random?random?=?new?Random();
????String?basic?=?"0123456789abcdefghijklmnopqrstuvwxyz"
????????????+?"ABCDEFGHIJKLMNOPQRSTUVWXYZ";
????for(int?i=0;i<10;i++){
????????StringBuffer?sb?=?new?StringBuffer();
????????int?num?=?random.nextInt(10)+1;
????????do{
??????????for(int?j=0;j<num;j++){
??????????????int?number?=?random.nextInt(basic.length());
??????????????sb.append(basic.charAt(number));
??????????}
????????}while(stringList.contains(sb));
????????String?stringSb?=sb.toString();
????????stringList.add(stringSb);
????????System.out.println("添加了字符串："+stringSb);
????}
????System.out.println("------------排序前-------------");
????for?(String?string?:?stringList)?{
????????System.out.println("元素："+string);
????}
????Collections.sort(stringList);
????System.out.println("------------排序后-------------");
????for?(String?string?:?stringList)?{
????????System.out.println("元素："+string);
中的int?number?=?random.nextInt(basic.length());
后面的能夠理解，但是前期的int number 有些不太確定是什么意思
2016-05-09