各位大神！求助，任務是判斷一個數（小于10位）的位數，輸入999，則輸出“它是個3位的數”
public class HelloWorld{
public static void main(String[] args){
int num = 999;
int count = 0;
if(num>=100&&num<=999)
{
? ? System.out.println("它是個3位的數")；
}else if (num>=10&&num<=99){
? ? "他是兩位數"
}
}
}
qq_沐曦_2
2016-02-27
2 回答
舉報
0/150
提交
取消
2016-02-27
import?java.util.Scanner; public?class?test?{ public?static?void?main(String[]?args){ Scanner?input?=?new?Scanner(System.in); System.out.print("請輸入:"); int?number?=?input.nextInt(); int?count?=?0; if(number?==?0){ System.out.println("它是個1位的數"); }else{ while(number?!=?0){ number?/=?10; count++; } System.out.println("它是個"+count+"位的數"); } } }2016-02-27
if (num >= 0 ?&& num<=999999999){
while(num != 0){
count++;
num/=10;
}
System.out.println("它是個"+ count+"位的數！");
} else{
System.out.println("輸入有誤！");
}