求1+2+3.......+n的值且n大于零小于200，這樣做對嗎
#include<stdio.h>
int main()
{
?int N,a;
?a=0;
?a=a+N;
?while (N>0&&N<200);
?N++;
?printf("%d\n","1到N的和") ;
?return 0;
八歲女鬼
2016-01-28
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2016-01-28
#include<stdio.h>
int main()
{
int n,sum=0;
printf("請輸入一個1至200的數:");
scanf("%d",&n);
if(n<1&&n>200)
printf("您輸入有誤.");
for(n;n>0;n--)
{
sum=sum+n;
}
printf("和為%d\n",sum);
return 0;
}
2016-01-28
#include<stdio.h>
int main()
{
?int N,a;
?while (N>0&&N<200)
{
a += N;
N++;
}
?printf("1到N的和為：%d\n",a) ;
?return 0;
2016-01-28
#include<stdio.h>
int main()
{
?int N,a;
?while (N>0&&N<200)
{
a +=
N++;
}
?printf("1到N的和為：%d\n",a) ;
?return 0;