請問為什么得出的結果全都是30 ？啥意思啊
package com.waiting;
public class Test {
public static void main(String[] args) {
? ? ? ? int one = 10 ;
? ? ? ? int two = 20 ;
? ? ? ? int three = 0 ;
? ? ? ? three=one+two;
? ? ? ? three+=one;
? ? ? ? three-=one;
? ? ? ? three*=one;
? ? ? ? three/=one;
? ? ? ? System.out.println("three=one+two==>"+three);
? ? ? ? System.out.println("three+=one==>"+three);
? ? ? ? System.out.println("three-=one==>"+three);
? ? ? ? System.out.println("three*=one==>"+three);
? ? ? ? System.out.println("three/=one==>"+three);
? ? ? ? System.out.println("three%=one==>"+three);
請問 有人幫我解答下嗎？這個代碼是不是應該這樣寫？結果怎么全都是最后一個數 ?30 ?30 ?30 3 0.。。。。啥意思啊
2016-01-01
你好，這么寫：
public?class?HelloWorld{ ????public?static?void?main(String[]?args)?{ ????int?one?=?10?; ????????int?two?=?20?; ????????int?three?=?0?; ????????three?=?one?+two; ????????System.out.println("three?=?one?+?two?==>"?+?three); ????????three?+=?one; ????????System.out.println("three?+=?one?==>"?+?three); ????????three?-=?one; ????????System.out.println("three?-=?one?==>"?+?three); ????????three?*=one; ????????System.out.println("three?*=?one?==>"?+?three); ????????three?/=one; ????????System.out.println("three?/=?one?==>"?+?three); ????????three?%=one; ????????System.out.println("three?%=?one?==>"?+?three);??? } }你的問題是把所有的運行語句執行后，最后輸出的，肯定結果都一樣，應該執行一條輸出一條，不然后會覆蓋，
望樓主采納！
2016-01-02
只輸出最后的結果，如果想把每一步的結果都輸出，那么要在每一步后面都有個sysout
2016-01-01
肯定是30，只輸出最后一個計算結果
?int?one?=?10?; ????????int?two?=?20?; ????????int?three?=?0?; ????????three=one+two;System.out.println("three=one+two==>"+three); ????????three+=one;System.out.println("three+=one==>"+three); ????????three-=one;System.out.println("three-=one==>"+three); ????????three*=one;System.out.println("three*=one==>"+three); ????????three/=one;System.out.println("three/=one==>"+three);